Suppose A and B are events with 0 LT PA LT 1 and 0 LT PB LT
Solution
Note that 1> P(A), P(B) >0
Two events A and B independent if and only if P(both A and B)=P(A)*P(B)
(a)
P(A and B)=0 (as A, B are disjoint)
But, P(A)*P(B) > 0
So, A and B are not independent.
(b)
A and B are independent.
P(A and B)=P(A)*P(B) > 0
So, A and B are not disjoint as P(A and B)>0
(c)
P(A and B)=P(A)
because A is a subset of B and thus, lies inside B. Whenever, A occurs B also occurs. That is, every element (or every outcome) of A also belongs to the event [A and B]. And obviously, every element of [A and B] is in A. So, the event [both A and B]=[B]
Now, P(A)> P(A)*P(B) (as P(B)<1)
So, P(A and B)=P(A)>P(A)*P(B)
Hence, A and B are not independent.
(d)
A is a subset of C= [A or B]
From part (c) A and C are not independent. That is, A and [A or B] are not independent.
