2 PROBLEM Compression Member l o 3 126 ft 6 y7 2 2 An axiall
Solution
a)let the centroid be at y\' as shown in the figure in question
y\'=(2*6*2*3 + 10*3*7.5)/(2*2*6+10*3)=5.5 in
moment of inertia about minor axis=2*2*63/12+2*2*6*(5.5-3)2+10*33/12+10*3*(7.5-5.5)2=364.5 in4
area of cross section=2*2*6+10*3=54 in2
radius of gyration=sqrt(364.5/54)=2.6 in
Effective length=26*0.707=18.38 ft=220.6 in
slenderness ratio=220.6/2.6=84.85
2) critical buckling stress = pi2*E/(KL/r)2=pi2*29000/84.852 = 39.76 ksi
3)nominal compressive strength = 39.76*54=2146.78 kips
4) design compressive strength=0.9*2146.78=1932.1 kips
