evaluate the integral of X2 4xSolutionwe have to calculate i

evaluate the integral of (X^2 -4)/x

we have to calculate integral of (x^2 -4)/x

as (x^2 -4)/x =((x^2)/x -(4/x))

integral of ((x^2)/x -4/x)

= integral of (x -(4/x))

=integral of x =(x^2)/2

=integral of 4/x =4ln(x)

integral of ((x^2)/x -4/x) =(x^2)/2 -4ln(x) +c

=(x^2)/2 -4ln(x) +c

Thank you