iPad 927 PM 96 actice Assignment Gradebook ORION nment MESSA

iPad 9:27 PM 96% actice Assignment Gradebook ORION nment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 12, Problem 001 Suppose you are hiking down the Grand Canyon. At the top, the temperature early in the morning is a cool 2.13 °C. By late afternoon, the temperature at the bottom of the canyon has warmed to a sweltering 34.5 °C. What is the difference between the higher and lower temperatures in (a) Fahrenheit degrees and (b) kelvins? (a) Number (b) Number Click if you would like to Show Work for this question: Units Units Open Show Work LINK TO TEXT LINK TO TEXT LINK TO TEXT Question Attempts: 0 of 5 used SVE FOR LATER su SUBMIT ANSWER Copyright © 2000-2016 by John Wiley & Sons, Inc. or related companies. All rights reserved.

Solution

Temprature difference in celsius dC =34.5 ^o C- 2.13 ^o C

                                                   = 32.37 ^o C

Relation between celsius sclae (C) and Fahrenheit scale (F ) is

C/100 = (F-32) /180

dC/100 = dF / 180

      dF = (180/100) dC

           =(9/5) dC

           =(9/5)32.37

           = 58.266 ^o F

(b). Relation between celsius scale(C) to Kelvin sclae(K) is

   C/100 = (K-273)/100

          C = K-273

       dC = dK

So, temprature difference in Kelvin scale dK = dC = 32.37 K

(3) (a) K = 367 kelvin

            = (367- 273 ) ^o C

            = 94 ^o C

(b). (F-32)/180 = (K-273) /100

            F-32 = (180/100) (K-273)

                    =(9/5)(367-273)

                   = 169.2

               F = 32 +169.2

                  = 201.2 ^o F

(c).K = 101 kelvin

            = (101- 273 ) ^o C

            = -172 ^o C

(b). (F-32)/180 = (K-273) /100

            F-32 = (180/100) (K-273)

                    =(9/5)(101-273)

                   = -309.6

               F = 32 -309.6

                  = -277.6 ^o F