A saturated sample has a mass 069 kilograms when wet and 05

A saturated sample has a mass 0.69 kilograms when wet and 0.5 kg when dry. Assuming that the specific gravity is 2.7, compute the void ratio, porosity and dry density of this material.

Solution

water content (w) = (wet weight -dry weigt)/dry weight

=(0.69-0.5)/0.5

=0.38

void ratio(e) = (wG)/s

=0.38*2.7/1

=1.026

porosity=(e/(1+e))

=1.026/(1+1.026)

=0.51

dry density=G*unit weight of water(1+e)

=2.7*62.43/(1+1.026)

=83.2 lb/ft3