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Question

1.

In the third procedure, a motion sensor measures the distance of a cart in time; relative distance from the motion sensor. (Remeber how you measured your height in exp 2) After the cart is released by the spring, the distance that motions sensor measures in a graph of displacement vs. time on the computer screen i)__________. Thus, we can say that the graph has a ii)______ slope. The slop of the curve, which corresponds to a velcoity of the cart, decreases in time due to kinetic frictional force, resulting in a iii) ______ acceleration.

Hint: the following equation, distance = 0.015 x time² - 0.201 x time + 0.801, should fit your data in procedure 3. (each value of coefficients is not important but the sign of them is crucial to answer this question.

i) increases, ii) negative, iii) positive

i) decreases, ii) negative, iii) positive

i) decreases, ii) positive, iii) negative

i) increases, ii) positive, iii) negative

i) increases, ii) positive, iii) positive

i) increases, ii) negative, iii) negative

i) decreases, ii) negative, iii) negative

i) decreases, ii) positive, iii) positive

2.

In a previous experiment, we graphed tension (on the y-axis) vs. acceleration (on the x-axis) in order to obtain the equation of the best-fit straight line for your data. Let\'s assume that the equation from your graph is y=0.411 x+0.28.

1-a) Use this result to determine f, the frctional force acting on the cart.
f = ___________ N

2b)

Use this result to determine m_c, the mass of the cart-plus-force senor.

m_c = ___________ kg

Comment

Comments

Solution

1. increases, positive, negative

2. comparing the given equation with y=mx+f

f= 0.28 N and mc= 0.411kg