A circus juggler tosses a ball straight upward from an initi

A circus juggler tosses a ball straight upward from an initial height of 2.8 m with an initial velocity of 14.7 m/sec.
If the acceleration due to gravity is 9.8 m/sec2, write an equation representing the height of the ball t seconds after
release.3. Use the equation from question 1 to determine how long will it take the ball to return to the juggler’s hand. ___________

Solution

Given: h₀=2.8 m, v₀ = 14.7 m/s , g = -9.8 m/s²

h(t) = h₀ + v₀t + (1/2)gt²

h(t) = 2.8+14.7t + (1/2)(-9.8)t²

h(t) = 2.8+14.7t - 4.9t²