A gas has 1027 degrees of freedom with a pressure of 150 atm

A gas has 10^27 degrees of freedom, with a pressure of 150 atm. It expands by 0.01 m^3 without any heat or particles added. (1 atm = 10\' N/m^2) Find the change in work W. Find the change in temperature Delta T.

work = p*change in volume = 150*10^5*.01 = 1.5 * 10^5 J
change in T = p * change in V / (n*R) =150* 10^5 * .01 / (8.3*10^27/(6.02*10^23)) (Ideal gas equation)
= 10.8 degree celcius

$A gas has 10^27 degrees of freedom, with a pressure of 150 atm. It expands by 0.01 m^3 without any heat or particles added. (1 atm = 10\' N/m^2) Find the chang$

A gas has 1027 degrees of freedom with a pressure of 150 atm

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