If necessary consult a list of formulas An urn contains oran

(If necessary, consult a list of formulas.)

An urn contains orange balls and red balls. If Juan chooses balls at random from the urn, what is the probability that he will select orange balls and red balls? Round your answer to decimal places. (If necessary, consult a list of formulas.)

Solution

There are 10C2 =    45   ways to choose orange balls.
      
There are 8C6 =    28   ways to choose the red balls.
      
[We chose combinations as the order you draw them does not matter.]      
      
Thus, there are 45*28 =    1260   ways toget the result.
      
There are a total of 18C8 =    43758   ways to get 8 balls out of 18.
      
Thus, the probability of the said result is 1260/43758 =    0.028794735 = 0.029 [ANSWER]