Homework SourseFind the mean and variance if they exist of the following di
Find the mean and variance, if they exist, of the following distribution
(a) p(x) = [3!/x!(3-x)!](1/2)^3, x=0,1,2,3, zero elsewhere
Solution
The given distribution is bionomial distribution with
n= 3
p = 1/2
q = 1/2
So,
MEAN = np = 3*1/2 = 1.5
VARIANCE = npq = 3*(1/2)*(1/2) = 3/4 = 0.75
^3, x=0,1,2,3, zero elsewhereSolutionThe given distributio](/WebImages/15/find-the-mean-and-variance-if-they-exist-of-the-following-di-1024807-1761530444-0.webp "Find the mean and variance, if they exist, of the following distribution (a) p(x) = [3!/x!(3-x)!](1/2)^3, x=0,1,2,3, zero elsewhereSolutionThe given distributio")
