I tried to use the formula dQdudw and came up with 50J but a

I tried to use the formula dQ=du+dw and came up with -50J but apperntly the answer is 0J. I am not sure of the steps that i need to use to get to that point.

Part A In an isochoric process, the internal (thermal) energy of an ideal gas decreases by 50 J. How much work does the gas do during this process? 25 J 0.00J 25 J 50 J 50 J Submit My Answers Give Up

Solution

Change in internal energy of an ideal das du = -50 J

Here negative sign indicates that internal energy id decreases.

In isochoric process,the volume of the gas remains constant.

i.e., volume V = constant

Change in volume dV = 0

Multiply both sides with pressure P you get,

   P dV = P(0)       

   = 0    

We know P dV = dW

Therefore work done during the process dW = 0