A box contains 6 red balls 9 blue balls and 4 green balls If

A box contains 6 red balls, 9 blue balls and 4 green balls.

If 10 balls are randomly selected (all at once), what is the probability that 3 will be red, 5 blue and 2 green?

Solution

Probability of selecting 3 red,5 blue and 2 green balls is

( 6C3 * 9C5* 4C2)/ 19C10 = 20* 126* 6/ 92376= 15120/92378 = 7560/ 46189