Au investor deposits 50 ill an investment account on January
Solution
Answer:
X = 236.25
Explaination:
The Investor Deposit 50 in an investment account on January 1.
On June 30, the Value of the account is 157.50. On December 31, the value of the account is X
According to the time-weighted method
The 6-month yield = (40/50)(80/60)(157.50/160) – 1
= 5%
Annual equivalent = (1.05)2 – 1
= 10.25%
1-year yield = (40/50)(80/60)(175/160)(X/250) – 1 = 0.1025
X(0.004667) = 1.1025
X = 236.25
Therefore on December 31st the value of account (X) = 236.25
