M McGrawHill Connect NX t GKIHS MembershipSX P Sample Exams2

M McGraw-Hill Connect N/X t GKIHS: Membership-S/X P Sample Exams-201727 x D Microsoft Word 0www.webassign.net/web/Student/Assignment-Responses/submit?dep=15010090 Quiz 3 × D SOLUTIONS Sample Q. X HW #18 TTh 3. 0/20 points | Previous Answers NorEngStatics 1 7.P.048 My Notes Ask Your Teacher Determine the surface areas in in2 and the volumes in in3 of the bodies of revolution obtained by revolving the bright blue shape one revolution around the following axes. The cutouts on each end are semicircular with 2.2 in. diameter. 2.2 in 1.1 in 2.2 in2.2 in_ (a) the y-axis A 237.454 in in (b) the x-axis in in Submit Answer Save Progress Practice Another Version 4. -120 points NorEngStatics 17. P. 052. My Notes Ask Your Teacher + Determine the volumes in mm3 of the solids generated by revolving triangular plate ABC (shown) one revolution about the following axes. 195 mm 234 mmm 10:48 AM Ask me anything 11/3/2016 21

Solution

volume of cyclinder = 3.14 x r square x h and surface area = 2 x 3.14x r x h , when substitute values we get Volume = 33.45 inch and Surface area as = 60.82

Same as two semi sphere is equal to one sphere = Volume of sphere = 4/3 x 3.14x r cube and surface area as = 4 x 3.14 x r square by substitute above values in formula we get, volume = 5.57 and Surface area as = 15.2

by deduction of Sphere cross section from cyclinder cross section will get answer