Concept Simulation 252 illustrates the concepts pertinent to

Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 2.50-cm-high object is situated 17.1 cm in front of a concave mirror that has a radius of curvature of 8.39 cm. Calculate the location and the height of the image.

Solution

h = 2.50 cm, u = - 17.1 cm

f = R/2 = -8.39 / 2 = - 4.195 cm

1/v + 1/u = 1/f

v = [f * u] / [u - f] = [- 17.1 *- 4.195] / [- 17.1 + 4.195]

= - 5.56 cm [the left of itself ]

--------------------------------------------------

magnification = m = h\'/ h = - v/u

h\' / 2.50 = - [- 5.56 /- 17.1]

h\' = - 0.813 cm [image is inverted]