In guinea pigs white coat w is recessive to black coat W and
Solution
Null hypothesis: Ho: The population is assorting independently.
Alternate hypothesis: H1: The population is not assorting independently.
The cross is:
W_V_ crossed to wwvv. Result is
Please note that test cross expected phenotypic ratio should be 1:1:1:1 in case of independent assortment (part ‘b’. Here, this is not the case.
Observed
Expected
(O-E)^2
(O-E)^2/E= chi square value
W_V_
30
20.75
85.5625
4.12349398
W_vv
10
20.75
115.563
5.56927711
wwV_
12
20.75
76.5625
3.68975904
wwvv
31
20.75
105.063
5.06325301
Total
83
18.4457831
Calculated value = 18.44
Degree of freedom = (rows-1) (columns-1) = (4-1)* (4-1) = 9
Tabulated value = taken from chi square table = 16.92
Level of significance (given) = 0.05
Null hypothesis is accepted if calculated value is less than tabulated value.
Here, tabulated value<calculated value, so, null hypothesis should be rejected.
So, the population is not assorting independently according to Mendelian ratio of 9:3:3:1 (part c). Chi-square test does not support the hypothesis.
Alternate hypothesis should be accepted.
| Observed | Expected | (O-E)^2 | (O-E)^2/E= chi square value | |
| W_V_ | 30 | 20.75 | 85.5625 | 4.12349398 |
| W_vv | 10 | 20.75 | 115.563 | 5.56927711 |
| wwV_ | 12 | 20.75 | 76.5625 | 3.68975904 |
| wwvv | 31 | 20.75 | 105.063 | 5.06325301 |
| Total | 83 | 18.4457831 |

