Question 12 How much ATP is formed in the BOxidation of fatt

Question 12 How much ATP is formed in the B-Oxidation of fatty acid? 30 300 0 0 pts

Solution

The one round of beta oxidation removes one molecule of acetyl-CoA, two pairs of electrons, and four protons from the long-chain fatty acyl–CoA, shortening it by two carbon atoms.
So, the equation can be given as following:
Fatty acyl CoA + CoA + FAD + NAD + H₂O-\\-->à Fatty acyl CoA (2 C shorter) + acetyl-CoA + FADH₂ + NADH + H

Each molecule of FADH₂ produces 1.5 molecules of ATP through ETS while each molecule of NADH forms about 2.5 molecules of ATP. Thus four molecules of ATP are formed for each two-carbon unit removed in one round of beta oxidation.
So, if we take a fatty acid with 16 C, the eight rounds of beta oxidation would produce 28 ATPs as per the following equation:
Fatty acyl CoA (16C) + 7 CoA + 7O₂ + 28Pi + 28ADP-->8 acetyl-CoA + 28ATPs + 7H₂O
So, a fatty acid with 18 C would give 30 ATPs.
Since one acetyl CoA gives 10 ATP upon entering the Kreb cycle, the 8 acetyl CoA would give 80 ATPs. This gives total 28+80= 108ATPs per fatty acid (16C).Considering the given options, if the fatty acid has 48C or is a triacyl, it will give total 108x3= 324 ATPs. The most appropriate answer is 300.