Knowing that P 150 lb and Q 90 lb determine the components

Knowing that P = 150 lb and Q = 90 lb, determine the components of all forces acting on member BCDE of the assembly shown. (Round the final answers to their nearest whole number.)

4 in 6 in. 6 in. in,- 44 in. The components of all forces acting on member BCDE are: 180 lb 252 lb B= lb lb

Solution

Given data:

Forces P=150 Ib = -150 Ib

Q=90 Ib =90Ib

Reaction at A =180 Ib =-180 Ib

Force at B = 252 Ib = -252 Ib

Direction of force. sign taken

& + ve

& - ve

Consider whole system :

For analysis external forces only considered

For equilibrium conditions

Sum of all forces in horizontal direction = 0

Q +Cx = 0

Cx = -90 Ib = 90 Ib ()

Sum of all forces in vertical direction =0

A+Cy + P = 0

-180+Cy-150=0

Cy= 330 Ib ()

Consider member BCDE only :

Forces acting at B& D also considered as external forces

Sum of all forces in horizontal direction = 0

Cx+Dx =0

Dx = 90Ib = 90 Ib

Sum of all vertical forces = 0

B+Cy+Dy+P=0

-252+330+Dy-150 =0

Dy= 72 Ib = 72 Ib