30 In a national standardized test Kimberly scored at the ni

30. In a national standardized test. Kimberly scored at the ninety-second percentile. If 67,500 individuals took the test, about how many scored higher than Kimberly?

Solution

L ---> number of person having marks less than kimberly

P-----> total numer of persons appeared for the test

percentile = L/P x 100

90 = L / 67500 x 100

L = 60750

total number of persons having more marks than kimberly = 67500 - 60750 = 6750.

 30. In a national standardized test. Kimberly scored at the ninety-second percentile. If 67,500 individuals took the test, about how many scored higher than Ki

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