1 You breed two rose species together one has large red flow

1. You breed two rose species together one has large red flowers and has thorns, the other has small yellow flowers and is thornless. the F1s all have small red flowers and thorns. You cross these F1s with a large yellow flowered thornless tester the resulting offspring were:

109 large red thorns 91 large red thornless 92 large yellow thorns

111 large yellow thornless 110 small red thorns

89 small red thornless

88 small yellow thorns 109 small yellow thornless

TABLE 5.1 Critical Chi-Square Values p values Cannot Reject the Null Hypothesis Null Hypothesis Rejected 0.10 0.01 0.001 0.99 0.90 0.50 0.05 Degrees of x Values Freedom 10.83 0.45 3.84 6.64 0.02 2.71 1.39 4.61 5.99 0.2 9.21 13.82 0.02 11.35 0.11 16.27 2.37 0.58 6.25 7.81 1.06 18.47 3.36 7.78 9.49 13.28 0.30 1.61 9.24 15.09 4.35 20.52 0.55 11.07 Note: x2 values that lie in the yellow region of this table allow you to reject the null hypothesis with 95% confidence, and for recombination experiments, to postulate linkage.

Solution

Answer:

Chi-square vale = 7.94

Total phenotypes=8

Degrees of freedom= Total phenotypes-1= 8-1 =7

Phenotype	Observed(O)	Expected (E)	O-E	(O-E)2	(O-E)2/E
large red thorns	109	99.88	9.12	83.17	0.83
large red thornless	91	99.88	-8.88	78.85	0.79
large yellow thorns	92	99.88	-7.88	62.09	0.62
large yellow thornless	111	99.88	11.12	123.65	1.24
small red thorns	110	99.88	10.12	102.41	1.03
small red thornless	89	99.88	-10.88	118.37	1.19
small yellow thorns	88	99.88	-11.88	141.13	1.41
small yellow thornless	109	99.88	9.12	83.17	0.83
Total	799	799.04			7.94