Let fx5x12x2 Then the equation of the tangent line to the gr

Let f(x)=5x+(12/x^2). Then the equation of the tangent line to the graph of f(x) at the point (2,14) is given by y=mx+b for

m=?

and

b=?

y = 5x + 12/x^2

dy/dx = 5 - 24/x^3

At 2,14, dy/dx = 5 - 24/2^3 = 2

y = -2 x + b

2,14 lies at this point

14 = -2.2 + b

b = 18

m = -2

b = 18