The mean height of women in a country ages 20minus29 is 638i

The mean height of women in a country (ages 20minus29) is 63.8inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume =2.67.

The probability that the mean height for the sample is greater than 64 inches is

(Round to four decimal places as needed.)

Solution

Mean ( u ) =63.8
Standard Deviation ( sd )=2.67
Number ( n ) = 75
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)                  
P(X > 64) = (64-63.8)/2.67/ Sqrt ( 75 )
= 0.2/0.308= 0.6487
= P ( Z >0.6487) From Standard Normal Table
= 0.2583