Sheilas doctor is concerned that she may suffer from gestati

Sheila\'s doctor is concerned that she may suffer from gestational diabetes (high blood glucose levels during pregnancy). There is variation both in the actual glucose level and in the blood test that measures the level. A patient is classified as having gestational diabetes if her glucose level is above 145 milligrams per deciliter (mg/dl) one hour after a sugary drink. Sheila\'s measured glucose level one hour after the sugary drink varies according to the Normal distribution with = 130 mg/dl and = 12 mg/dl.

Let X = Sheila\'s measured glucose level one hour after a sugary drink

(a) P(X > 145) =   (Use 3 decimal places)

Suppose measurements are made on 5 separate days and the mean result is compared with the criterion 145 mg/dl.

(b) P(X > 145) =  (Use 3 decimal places)

(c) What sample mean blood glucose level is higher than 95% of all other sample mean blood glucose levels? Hint: this requires a backward Normal calculation. (Use 2 decimal places)

Solution

a)
Mean ( u ) =130
Standard Deviation ( sd )=12
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X > 145) = (145-130)/12
= 15/12 = 1.25
= P ( Z >1.25) From Standard Normal Table
= 0.106                  
b)
Standard Deviation ( sd )=12
Number ( n ) = 5
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)                  

P(X > 145) = (145-130)/12/ Sqrt ( 5 )
= 15/5.367= 2.7951
= P ( Z >2.7951) From Standard Normal Table
= 0.003                  
c)
P ( Z > x ) = 0.95
Value of z to the cumulative probability of 0.95 from normal table is -1.64
P( x-u/ (s.d) > x - 130/12) = 0.95
That is, ( x - 130/12) = -1.64
--> x = -1.64 * 12+130 = 110.26