Find all solutions of the equation in 0 2 2 cos 2 x sinx 1
Find all solutions of the equation in [0, 2). 2 cos ^2 \\(x\\) + sin(x) = 1
Solution
2cos^2x+sinx=1 for 0 < x < 360 deg
 2(1-sin^2x)+sinx=1
 2-2sin^2x+sinx=1
 -2sin^2x+sinx+1=0
 2sin^2x-sinx-1=0
 (2sinx+1)(sinx-1)=0
 ..
 
 2sinx+1=0
 sinx=-1/2
 x=210º and 330º (in quadrants III and IV where sin<0)
 ..
 sinx-1=0
 sinx=1
 x=90º
 ..
 ans:
 x=210º, 330º and 90º

