Determine the shortest time possible for the rearwheel drive
Determine the shortest time possible for the rear-wheel drive, 2-Mg truck to achieve a speed of 19 m/s with a constant acceleration starting from rest. The coefficient of static friction between the wheels and the road surface is mu_s = 0.7. The front wheels are free to roll. Neglect the mass of the wheels.
Solution
Answer -
Acceleration(a) = (Coeffcient of friction x Total Normal Force) / Total Mass
a = 1.4 x g [ g = acceleration due to gravity ] [ x= multiplication term]
Now using basic equation for constant acceleration
v = u + at [ v&u are final and initial velocities, t is time]
t = v-u/a
t = 19/(1.4 x 9.8)
t = 1.3 sec
