Find the instantaneous values of sine wave A B and C from th
Find the instantaneous values of sine wave A. B and C (from the figure below at 10 degree 40 degree 160 degree
Solution
WE CAN WRITE EQUATION FOR A
A=5sin(T+30)
.SO AT T=10 A=5sin(T+30)=5SIn(40)=3.2139V.
T=40,A=5sin(T+30)=5SIn(70)=4.698V
T=1600 A=5sin(T+30)=5SIn(190)=-.868V
EQUATION FOR B=10SIn(T)
AT T=10, B=10sin(10)=1.736V
T=40, B=10sin(40)=6.4278V
T=160, B=10sin(160)=3.402V
EQUATION FOR C=15sin(T-90)
T=10, C=15sin(10-90)=-14.772V
T=40 C=15sin(40-90)=-11.49V
T=160, C=15sin(160-90)=14.095
