In the frame shown below dimension H is 6m y is 4m L is 8m x

In the frame shown below dimension H is 6m, y is 4m, L is 8m, x is 3m, I is 3m, h is 5m. External loads are: the vertical point load P of 4kN is applied at D, the clockwise moment M of 3kNm is applied at B, the vertical uniformly distributed load w of 2kN/m is applied on bar FJ. Calculate reactions of supports. Give you answer (to one decimal point accuracy) in kN for force reactions and in kNm for moment reactions. Don\'t write units. Assume positive reactions in directions of coordinates X and Y for forces and clockwise for moments. Write negative values with sign and positive without sign. Write 0.0 for non-existing reactions. Vertical reactions: V_a= [VA], V_g=[VG], V_k=[VK] Horizontal reactions: H_a= [HA], H_g=[HG], H_k=[HK]. Moment reactions: M_a= [MA], M_g=[MG], M_k=[MK]. Specified Answer for: VA 0.0 Specified Answer for: VG 7 Specified Answer for: VK 3 Specified Answer for: HA 0.5 Specified Answer for: HG 1 Specified Answer for: HK 1 Specified Answer for: MA 0.0 Specified Answer for: MG 14 Specified Answer for: MK 0.0 Divide the frame shown above into free bodies and calculate end forces on these free bodies. Give you answers (to one decimal point accuracy) in kN for end forces and in kNm for end moments. Don\'t write units. Assume positive moments if they put outside of the frame in tension. Write negative values with sign and positive without sign. Write 0.0 for non-existing end forces. Axial forces: A_cd= [ACD], A_ed=[AED], A_ef=[AEFl Shear forces: S_cd= [SCD], S_ef=[SED], S_ef=[SEF]. End moments: M_cd= [MCD], M_ed=[MED], M_ef=[MEF]. Specified Answer for: ACD 1.0 Specified Answer for: AED 1.0 Specified Answer for: AEF 4.0 Specified Answer for: SCD 0.0 Specified Answer for: SED 20.0 Specified Answer for: SEF 3.0 Specified Answer for: MCD 0.5 Specified Answer for: MED 0.5 Specified Answer for: MEF 4.0 For the frame shown above draw AFD, SFD, and BMD and determine some key values from these diagrams. Give you answers (to one decimal point accuracy) in kN for forces and in kNm for moments. Don\'t write units. Assume positive moments if they put outside of the frame in tension. Write negative values with sign and positive without sign. Write 0.0 for non-existing internal forces. Forces with maximum (positive or negative) magnitude: A_max=[AMAX], S_max=[SMAX], M_max=[MMAX]. Values immediately above point F: A_^f[AF], S_^f[SF], M_^f[MF]. Specified Answer for: AMAX 11 Specified Answer for: SMAX 6 Specified Answer for: MMAX 20 Specified Answer for: AF [None Given] Specified Answer for: SF [None Given] Specified Answer for: MF [None Given]

Solution

The loaded four wheel trailer shown in Figure P8.10 has a total mass of 5t and is pulled along a level road. Average resistance to motion (friction and windage) is 2 per cent of the total weight and acts at the same horizontal level as the applied force P. Determine the normal reaction at each of the front and rear wheels when the trailer moves:

a) at constant velocity

b) with forward acceleration 1.5m/s².

(Average resistance to motion is 2% of total weight is not required.)