Write an equation for the hyperbola shown in the graph The e
Solution
Given : asymtotes y = +/-2x
y = +/- bx/a
So, b/a = 2
b^2 = 4a^2
Hypebola has ecntre (0, 0)
Equation would be of the form : x^2/a^2 -y^2/b^2 =1
x^2 /a^2 +y^2/4a^2 =1
x^2 + y^2/4 = a^2 ----(1)
b = 2a
we need one point through which hyperbola passes which is not visble in the diagram
Plug that point and calculate a
Substitute value of a in x^2 /a^2 +y^2/4a^2 =1 and get equation of hyperbola
