b 3S c D Solutiona 5 b c 10 A B 35 degree C Now b

Solution

a = 5

b = ?

c = 10

A = ?

B = 35 degree

C = ?

Now b = sqrt[a^2 + c^2 – 2ac*cosB] = sqrt[5^2 + 10^2 – 2*5*10*cos35] = 6.6

Also a = sqrt[b^2 + c^2 – 2bc*cosA] ==> 5 = sqrt[6.6^2 + 10^2 – 2*6.6*10*cosA]===> A = 26.1 degree

And c = sqrt[a^2 + b^2 – 2ab*cosC] ==> 10 = sqrt[5^2 + 6.6^2 – 2*6.6*5*cosC]===> A = 118.5