pt For the following functions usex to indicate that the rax
Solution
a) f(x) = x/(x-1)^2
the degree on the denominator (namely, 2) was bigger than the degree on the numerator (namely, 1), and the horizontal asymptote was y = 0 (the x-axis).
So, Horizontal asymtote : x axis---- x
Vertcial asymtote : x =1 ------ v
No slant asymtote
b) f(x) = x^2/(x-1)^2
So, Horizontal asymtote : y = x^2/x^2 =1
y =1------ h
Vertcial asymtote : x =1 ------ v
No slant asymtote
c) f(x) = x^3/(x-1)^2
Vertcial asymtote : x =1 ------ v
Slant Asymtote: if the degree of the numerator is exactly one more than the degree of the denominator (so that the polynomial fraction is \"improper\"), then the graph of the rational function will be, roughly, a slanty straight line
Divide : x^3/(x-1)^2 = x+2
y = x+2 ---------- s
d) f(x) = x^2/(x^2+1)
Horizontal asymtote:
y = x^2/x^2 = 1
y =1 ----h
Vertical asymtote:
none
Slant asymtote:
none
