The bottlers of a new fruit juice daily select a random samp

The bottlers of a new fruit juice daily select a random sample of 12 bottles of the drink to estimate the mean quantity of juice in the bottles filled that day. On one such day, the following results were observed: = 12.03; s = 0.12. Based on this information, the margin of error associated with a 90 percent confidence interval estimate for the population mean is 1.7959 ounces

Solution

The 90% CI is:

Mean +/-margin of error

=(12.03+/-1.7959)

=(10.2341,13.8259)