Given y1x x3 29 is a solution to y 2y 3y x and y2x e2x
Given y1(x) = (-x/3) - (2/9) is a solution to y\'\' + 2y\' - 3y = x and y2(x) = (e^(2x))/5 is a solution to y\'\' + 2y\' - 3y = e^(2x). Find a solution to y\'\' + 2y\' - 3y = 4x - 5e^(2x)
Solution
4[(-x/3)-(2/9)]-5[e^(2x)/5]
-4x/3-8/9-e^2x is a solution to y\'\' + 2y\' - 3y = 4x - 5e^(2x)
