Consider the function fx cos03x2 For the value of cos03x2 t

Consider the function f(x) = cos(0.3(x-2)). For the value of cos(0.3(x-2)) to cycle through its output values once, the value of the arguments, 0.3 (x-2), must vary from 0 to 2 pi. This means the value of x must vary from What is the period of function f? Consider the function f(x) = sin(2 pi x - 0.3). For the value of sin(2 pi x - 0.3) to cycle through its output values once, the value of the argument, 2 pi x - 0.3, must vary from 0 to 2 pi. This means the value of 2 must vary from What is the period of function f?

Solution

a) f(x)=cos(0.3(x-2))

i)0.3(x-2)=0

=>x=2

0.3(x-2)=2

x-2=20/3

x=2+(20/3)

x must vary from 2 to 2+(20/3)

ii)period of f =2/0.3

period of f =20/3

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b)i)f(x)=sin(2x -0.3)

2x -0.3=0

2x=0.3

x=0.3/(2)

x=3/(20)

2x -0.3=2

2x=2+0.3

x=1+(0.3/(2))

x=1+(3/(20))

x must vary from 3/(20) to 1+(3/(20))

ii)period of f =2/(2)

period of f=1