The domain of the function gx x 3Squareroot x 5 is x note

The domain of the function g(x) = x - 3/Squareroot x + 5 is: x notequalto -5 x notequalto 3 x greaterthanorequalto -5 x > -5

Solution

g(x) = (x-3)/sqrt(x+5)

Now sqrt(x+5) should have x+5>=0

This means that g(x) can be = (x-3)/0

But denominator cannot be zero.

So, x+5>0

x > -5

Option D