The figure shows a uniform beam of these m provided at its b
Solution
sum the moments about the hinge
sigma M = (k d L sin theta) - (m g * 1/2 * L * cos theta ) = 0
(k d sin theta) - (m g * 1/2 * cos theta ) = 0
(k d sin theta) = (m g * 1/2 * cos theta )
d = (m g cos theta) / (2 k sin theta)
d = m g / 2 k tan theta
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Fx = k d
Fy = m g
