A 0150 kg block is placed on a light vertical spring k 480

A 0.150 kg block is placed on a light vertical spring (k = 4.80 10³ N/m) and pushed downward, compressing the spring 0.100 m. After the block is released, it leaves the spring and continues to travel upward. What height above the point of release will the block reach if air resistance is negligible?
1 m

Solution

the length of the compression in the spring = 0.100m = x

the total potential enrgy of the compressed spring = kx^2/2 = 4.80*10^3 * 0.100^2 / 2 ^= 24J

if the whole spring potential energy is transmitted to the block by which the block reach a height h acquiring gravitational potential energy = mgh

             mgh = 24 J

                h = 24 / m*g = 24 / 0.150 kg * 9.8 m/s2

                    = 16.326 m