Find the mean and variance in normal approximation of the bi

Find the mean and variance in normal approximation of the binomial. Find mu and sigma^2. 5.97 n = 100,p = 0.3 5.101 n=135,p=2/7

Solution

1)

mean = n*p = 100*0.3 = 30

variance = n*p*(1-p) = 100*0.3*0.7 = 21

2)

mean = n*p = 135*2/7 = 38.57

variance = n*p*(1-p) = 135*(2/7)*(5/7) = 27.55

 Find the mean and variance in normal approximation of the binomial. Find mu and sigma^2. 5.97 n = 100,p = 0.3 5.101 n=135,p=2/7 Solution1) mean = n*p = 100*0.3

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