Let fx9x9x2 Then the equation of the tangent line to the gra

Let f(x)=9x+(9/x^2). Then the equation of the tangent line to the graph of f(x) at the point (2,21) is given by y=mx+b for

m=?

and

b=?

f\'(x) = 9 - 18/x³

SO, we have,

f\'(2) = 9 - 18/9³

= 727/81

So, we have,

eqn of tangent as:

y - 21 = (x-2)(727/81)

So, we have, m = 727/81 , b = -2 x 727/81 + 21 = 247/81

$Let f(x)=9x+(9/x^2). Then the equation of the tangent line to the graph of f(x) at the point (2,21) is given by y=mx+b for m=? and b=?Solutionf\'(x) = 9 - 18/x3$

Let fx9x9x2 Then the equation of the tangent line to the gra

Solution

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