for a sample qith a mean of M 51 a score of X 59 correspon

for a sample qith a mean of M = 51, a score of X = 59 corresponds to z = 2.00. what is the sample standard deviation?

Solution

Normal Distribution
Mean ( u ) =51
Standard Deviation ( sd )= Unknown
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
2.00 = 59 - 51 / sd
sd = 8/2
sd = 4