A B CSolutionA Area of sector A n360r2 given n 225 r 25f

A) Area of sector A = (n/360)r²

given n = 225 , r = 2.5ft

==> A = (225/360)(2.5)² = (5/8)(6.25)

==> A = 12.272 ft²

B) length of arc = ( * /180) * r

given length of arc = 3.3 cm , r = 6 cm

==> 3.3 = ( * /180) * 6

==> = (3.3/6)(180/)

==> = 31.523 degrees