Hypothesis Testing Question Show all worrk Thank youSolution

Hypothesis Testing Question

Show all worrk, Thank you.

Solution

Let mu be the population mean

The test hypothesis:

Ho: mu=15 (i.e. null hypotheiss)

Ha: mu not equal to 15 (i.e. alternatve hypothesis)

The test statistic is

Z=(xbar-mu)/(s/vn)

=(15.6-15)/(1/sqrt(49))

=4.2

It is a two-tailed test.

Given a=0.01, the critical values are Z(0.005) = -2.58 or 2.58 (from standard normal table)

The rejection regions are if Z<-2.58 or Z>2.58, we reject the null hypothesis.

Since Z=4.2 is larger than 2.58, we reject the null hypothesis.

So we can conclude that there is evidence to support the claim

Hypothesis Testing Question Show all worrk, Thank you.SolutionLet mu be the population mean The test hypothesis: Ho: mu=15 (i.e. null hypotheiss) Ha: mu not equ

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