A male bird with black fur is mated to a female bird with ye

A male bird with black fur is mated to a female bird with yellow fur. The female has 7 babies. Four of the babies have black fur and three have yellow fur. Use the symbol B for the dominant allele and the symbol b to represent the recessive allele.

What is the recessive phenotype?

Use the symbols provided to indicate the genotype of the male bird (The father of the 7 babies).

Which is the genotype of the female bird (the mother of the babies): Homozygous dominant, homozygous recessive, or heterozygous?

One of the male babies with black fur is mated to one of his sisters with yellow fur. She has 8 babies, seven of which have black fur and one of which has yellow fur. Use the symbols provided to indicate the genotype of the male bird with black fur. (The father of the 8 babies.)

Solution

a). Assume that the gene coding for black fur is, B and the gene coding for yellow fur is b; B is dominant over b.

Given that mating between a male with black fur and a female with yellow fur resulted in offspring with both the black and yellow fur. Means, the male is heterozygous for B and female is homozygous for b.

Bb (black male)* bb (yellow female) --à Bb (1/2, black), bb (1/2, yellow)

1: 1 ratio of black to yellow phenotype progeny.

b). Thus, the mother’s genotype is, homozygous recessive.

c). A male baby with black fur is mated to a female with the yellow fur. Of the total eight babies, they had seven babies with black fur and one baby with yellow fur. Means, the father u=is heterozygous and the genotype is, Bb

Bb* bb -à Bb (1/2, black) and bb (1/2, yellow)