How many different elements does A x B x C have if A has m e
How many different elements does A x B x C have if A has m elements, B has n elements, and C has p elements?
Solution
The number of elements in the AXB is given by (number of elements in A) * (number of elements in B)
Ex - A = (1.2) and B = (3,4,5)
AXB = { (1,3),(1,4),(1,5),(2,3),(2,4),(2,5)}, which is equal to 2X3 = 6 elements
Hence AXB contains mn elements
Now assuming D = AXB
then DXC will contain (number of elements in D) * (number of elements in C)
=> (number of elements in (AXB)) * (number of elements in C)
=> (m*n) * p
= (mnp)
Hence the number of different elements in A x B x C is equal to mnp elements
