xsquare root2x9dxSolutionintegralx2x9dx put 2x9t xt92 and dx
(x(square root(2x+9)))dx
Solution
integral(x((2x+9)))dx
put 2x+9=t
==>x=(t-9)/2 and dx=dt/2
integral(x((2x+9)))dx
=integral((t-9)(t))dt/4
=integral((t^(3/2)-9t))dt/4
=(2t^(5/2) /5 -6t^(3/2)))/4+c
=(2( 2x+9)^(5/2) /5 -6( 2x+9)^(3/2)))/4+c
