Evaluate a piecewise defined function fx 1x if 0 lessthanor

Evaluate a piecewise defined function. f(x) = {.1x if 0 lessthanorequalto x lessthanorequalto 8000 800 + 0.15 (x - 8000) if 8000

Solution

Since f(5000) falls in the first interval that is from 0 to 8000. Therefore:

f(5000) = .1x = .1*5000 = 500

Now, f(15000) falls in the interval above 8000. Therefore:

f(15000) = 800 + 0.15(x - 8000)

f(15000) = 800 + 0.15(15000 - 8000)

f(15000) = 800 + 0.15*7000

f(15000) = 800 + 1050

f(15000) = 1850

 Evaluate a piecewise defined function. f(x) = {.1x if 0 lessthanorequalto x lessthanorequalto 8000 800 + 0.15 (x - 8000) if 8000 SolutionSince f(5000) falls in

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