find the margin of error for the 95 confidence interval used

find the margin of error for the 95% confidence interval used to estimate the population.N= 460, x =60

Solution

Given :

N=460 , x= 60 , confidence =95%

Solution:

Population proportion p = 60/460 = 0.13

q =1 - 0.13 = 0.87

Therefore,

Margin of error (MOE) = 1.96 * sqrt(p*q)/N

= 1.96 * sqrt ((0.13*0.87)/460) = 0.0308 Answer