Let X1 X48 be a random sample subject to uniform 1 2 1

Let X1, . . . , X48 be a random sample subject to uniform ( -1/ 2 , 1/ 2 ) and X = X1 +

A randome variable X being subject to (1/2. -1/2) implies that the these are the max and the min values the variable can assume.

(1)Putting these values under the programming process the E(Xi) would imply finding mean sub to (1/2, -1/2)

which would equal 1/6

and the Var(Xi) would be the square of the sum of the deviations form this mean which would be 25.

Note : this can also be solved using the LP Excel format

(2) P(IXI) < or = 2 would be 1.2

(3) The value for P ( -1< and equal X and equal 3) would eqaul 3.3