the probability that z lies between 110 and 036SolutionFor a

the probability that z lies between -1.10 and -0.36

Solution

For a random variable Z following a Standard Normal Distribution : N(0,1)

P(-1.10 < Z < -0.36)

= P(Z<-0.36) - P(Z<-1.10)

From standard normal tables,

= 0.35942 - 0.13567

= 0.22375