Suppose the emf of the battery in the circuit shown in the f

Suppose the emf of the battery in the circuit shown in the figure below varies with time t so that the current is given by

i(t) = 3.0 + 5.8t

Solution

Applying the Kirchoff\'s Loop rule

E-LdI/dt =IR

E=L(dI/dt)+IR

E=(5.5)[(d/d)(3+5.8t)] +4.8(3+5.8t)

E=5.5*5.8 + 4.8*3+4.8*5.8*t

E=(46.3+10.6t)