PLEASE HELP The point charges in Figure 1741 are located at

PLEASE HELP! The point charges in Figure 17.41 are located at the corners of an equilateral triangle 25.0 cm on a side, where qb = +16.0 µC and qc = -5.00 µC. (Assume that the +x-axis is directed to the right.)

A) Find the electric field at the location of qa.

-Magnitude

-Direction ° (counterclockwise from the +x-axis)

B)What is the force on qa, given that qa = +1.50 nC?

-Magnitude

-Direction ° (counterclockwise from the +x-axis)

Solution

a)

the electric field, E_b = kq_b/r² = 2.304*10⁶ N/C

the electric field, E_c = kq_c/r² = 7.2*10⁵ N/C

x-component: Ex = E_bcos 60+E_ccos 60 = 1.512*10⁶ N/C

y-component: Ey = E_bsin 60-E_csin 60 = 1.3717*10⁶N/C

net electric field: E_net = sqrt [Ex^2 + Ey^2] = 2.04*10⁶N/C

Direction: @ =Tan ^-1(Ey/Ex) = 42.2^o

b)

the force is, F = q_a*E =3.06*10^-3 N = 3.06 mN

Direction: @ =Tan ^-1(Ey/Ex) = 42.2^o